c++17方案
auto f = [](int a, double b, std::string c) { std::cout<<a<<" "<<b<<" "<<c<< std::endl; };
auto params = std::make_tuple(1,2.0,"Hello");
std::apply(f, params);
c++14方案
#include <vector>
#include <iostream>
#include <iomanip>
#include <chrono>
#include <memory>
#include <cmath>
#include <algorithm>
#include <type_traits>
#include <iostream>
#include <functional>
#include <complex>
void f(int a, double b, void* c)
{
std::cout << a << ":" << b << ":" << c << std::endl;
}
template<typename Function, typename Tuple, size_t ... I>
auto call(Function f, Tuple t, std::index_sequence<I ...>)
{
return f(std::get<I>(t) ...);
}
template<typename Function, typename Tuple>
auto call(Function f, Tuple t)
{
static constexpr auto size = std::tuple_size<Tuple>::value;
return call(f, t, std::make_index_sequence<size>{});
}
int main()
{
std::tuple<int, double, int*> t;
call(f, t);
}
来源参考
https://stackoverflow.com/questions/7858817/unpacking-a-tuple-to-call-a-matching-function-pointer